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: Condition I: : Surface Plasmon Resonance (SPR) : Boundary conditions at interfaces

Refelction and Transmission

Now we define the incident plane wave

\begin{displaymath}
{\bf E}={\bf E}_0 e^{i({\bf k}\cdot{\bf r} - \omega t)}, \ \...
...imes {\bf E}_0 }{\omega} e^{i({\bf k}\cdot{\bf r} - \omega t)}
\end{displaymath} (51)

reflected wave
\begin{displaymath}
{\bf E}' ={\bf R}_0 e^{i({\bf k}'\cdot{\bf r} - \omega' t)},...
...s {\bf R}_0 }{\omega'} e^{i({\bf k}'\cdot{\bf r} - \omega' t)}
\end{displaymath} (52)

transmitted wave
\begin{displaymath}
{\bf E}''={\bf T}_0 e^{i({\bf k}''\cdot{\bf r} - \omega'' t)...
... T}_0 }{\omega'' }
e^{i({\bf k}'' \cdot{\bf r} - \omega'' t)}
\end{displaymath} (53)

図 3: Relection and Transmission of Light
\includegraphics[width=12cm]{ref_trans.eps}

From the Figure above

$\displaystyle {\bf k}$ $\textstyle =$ $\displaystyle (k\sin\theta, 0, k\cos\theta)$ (54)
$\displaystyle {\bf k}'$ $\textstyle =$ $\displaystyle (k'\sin\theta', 0, k'\cos\theta'), \ \ \ \ \ \ \
e^{i(\pi - \theta')} = -\cos \theta' + i \sin\theta'$ (55)
$\displaystyle {\bf k}''$ $\textstyle =$ $\displaystyle (k'' \sin\theta'' , 0, k'' \cos\theta'' )$ (56)

The $p$-wave has component of $x$ and $z$, but $s$-wave has only $y$ component.




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: Condition I: : Surface Plasmon Resonance (SPR) : Boundary conditions at interfaces
Yamamoto Masahiro 平成14年8月30日